Walt Wrote:In the world of HHO you can predict the heat of your cell by the wattage input ((Wx3.4)/LBS water)xhours)) excuse poor algebra. To control the heat you can add more heat absorbing water, use a container that looses heat easily, adjust catylist, or add a resistor.

I would edit that last sentence a little. While adding a resistor may reduce the heat in the cell you are just creating an inefficiency with a resistor. The best way to lower cell heat/wattage is to lower the volts per cell which is most easily done by adding more sealed cells in series.

Watts are calculated by volts x amps. If you are running a parallel type generator supplying full 14 volts @ 10 amps to the single cell you are generating 140 watts or about 478 BTU/hr. If you run cells in series and get the VPC (volts per cell) down to 2.5 still running at 10 amps you are only generating 25 watts or about 85 BTU/hr. The difference is significant and production will be pretty much the same.

I'm running 6 cells in series currently which equates to about 2.2 vpc. After 1.5 hours of running the electrolyte temp was ~2*F above ambient which where it was mounted was 118*F. By comparison I had 5 cells running last week which provided about 2.6 vpc and after the same drive the electrolyte would exceed 150-160*F at the same ambient temp. Hardware lasts much longer and the amperage remains much more stable at lower volts per cell. Plus you get a significant more volume of gas at the same amperage in this configuration.

Through my research HHO production is a product of amperage. Watts/BTU's are not the primary factor in the equation. Some heat will assist in gas production but is not the primary factor.

As far as "horsepower per liter", this also greatly depends on your generators efficiency. If you convert the total watts (25x6 in my example above) you get 150 watts total for the generator. This converts to .2 horsepower. Given losses in the charging system I imagine it takes a little more than .2 HP to run the generator at 10 amps but not much.

Walt Wrote:...I think a good production is around 200 Watts per liter. In 1 gallon of water 200 watts is 680 BTU. 1 gallon is 8.23lb. That is an 82 degree gain in one hour (not considering heat loss). Heat loss depends on the container and the ambient temp of the environment. Calculating heat loss is not a difficult chore with just a crude experiment and a themometer.

I think you are right, that is a decent number IF those watts are divided through several cells. All those watts/BTU's in a single cell will generate way too much heat. Divided through 6 cells, for instance, you only need about 33 watts per cell to achieve your 200 watts total. That comes out to about 14 amps running through your generator @ 14 volts total (2.33 vpc). But again, HHO production is not a product of heat, it's the current breaking the hydrogen and oxygen bond.